Base | Representation |
---|---|
bin | 110001100110110011… |
… | …010010111010101101 |
3 | 12002111002020100010021 |
4 | 301212303102322231 |
5 | 1333041132033123 |
6 | 40245211242141 |
7 | 3563640224020 |
oct | 614663227255 |
9 | 162432210107 |
10 | 53264330413 |
11 | 20653364888 |
12 | a3a6149351 |
13 | 503b143598 |
14 | 28140a31b7 |
15 | 15bb24dc5d |
hex | c66cd2ead |
53264330413 has 4 divisors (see below), whose sum is σ = 60873520480. Its totient is φ = 45655140348.
The previous prime is 53264330411. The next prime is 53264330459. The reversal of 53264330413 is 31403346235.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 53264330413 - 21 = 53264330411 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53264330411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3804595023 + ... + 3804595036.
It is an arithmetic number, because the mean of its divisors is an integer number (15218380120).
Almost surely, 253264330413 is an apocalyptic number.
It is an amenable number.
53264330413 is a deficient number, since it is larger than the sum of its proper divisors (7609190067).
53264330413 is an equidigital number, since it uses as much as digits as its factorization.
53264330413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7609190066.
The product of its (nonzero) digits is 77760, while the sum is 34.
Adding to 53264330413 its reverse (31403346235), we get a palindrome (84667676648).
The spelling of 53264330413 in words is "fifty-three billion, two hundred sixty-four million, three hundred thirty thousand, four hundred thirteen".
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