Base | Representation |
---|---|
bin | 1111100000100100000… |
… | …00101000011100010001 |
3 | 1212221110012011020220212 |
4 | 13300102000220130101 |
5 | 32212313243201431 |
6 | 1044444551013505 |
7 | 53333134055114 |
oct | 7602200503421 |
9 | 1787405136825 |
10 | 532878100241 |
11 | 195aa0882873 |
12 | 8733796a295 |
13 | 3b333886866 |
14 | 1bb119c257b |
15 | dcdc27272b |
hex | 7c12028711 |
532878100241 has 2 divisors, whose sum is σ = 532878100242. Its totient is φ = 532878100240.
The previous prime is 532878100211. The next prime is 532878100243. The reversal of 532878100241 is 142001878235.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 532878100225 + 16 = 729985^2 + 4^2 .
It is a cyclic number.
It is not a de Polignac number, because 532878100241 - 222 = 532873905937 is a prime.
Together with 532878100243, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (532878100243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 266439050120 + 266439050121.
It is an arithmetic number, because the mean of its divisors is an integer number (266439050121).
Almost surely, 2532878100241 is an apocalyptic number.
It is an amenable number.
532878100241 is a deficient number, since it is larger than the sum of its proper divisors (1).
532878100241 is an equidigital number, since it uses as much as digits as its factorization.
532878100241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 107520, while the sum is 41.
Adding to 532878100241 its reverse (142001878235), we get a palindrome (674879978476).
The spelling of 532878100241 in words is "five hundred thirty-two billion, eight hundred seventy-eight million, one hundred thousand, two hundred forty-one".
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