Base | Representation |
---|---|
bin | 110001101000111111… |
… | …010100000100110101 |
3 | 12002120122022010210011 |
4 | 301220333110010311 |
5 | 1333130031112232 |
6 | 40253002100221 |
7 | 3564564216265 |
oct | 615077240465 |
9 | 162518263704 |
10 | 53301035317 |
11 | 20672054812 |
12 | a3b64aa671 |
13 | 504592536a |
14 | 2818cd97a5 |
15 | 15be59e547 |
hex | c68fd4135 |
53301035317 has 2 divisors, whose sum is σ = 53301035318. Its totient is φ = 53301035316.
The previous prime is 53301035311. The next prime is 53301035327. The reversal of 53301035317 is 71353010335.
53301035317 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 30012444081 + 23288591236 = 173241^2 + 152606^2 .
It is a cyclic number.
It is not a de Polignac number, because 53301035317 - 23 = 53301035309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53301035311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26650517658 + 26650517659.
It is an arithmetic number, because the mean of its divisors is an integer number (26650517659).
Almost surely, 253301035317 is an apocalyptic number.
It is an amenable number.
53301035317 is a deficient number, since it is larger than the sum of its proper divisors (1).
53301035317 is an equidigital number, since it uses as much as digits as its factorization.
53301035317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14175, while the sum is 31.
The spelling of 53301035317 in words is "fifty-three billion, three hundred one million, thirty-five thousand, three hundred seventeen".
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