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53301401 = 503105967
BaseRepresentation
bin1100101101010…
…1000010011001
310201021222202222
43023111002121
5102121121101
65142233425
71215024446
oct313250231
9121258688
1053301401
11280a614a
1215a25875
13b072cba
1471169cd
154a2d01b
hex32d5099

53301401 has 4 divisors (see below), whose sum is σ = 53407872. Its totient is φ = 53194932.

The previous prime is 53301397. The next prime is 53301427. The reversal of 53301401 is 10410335.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53301401 - 22 = 53301397 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 53301401.

It is not an unprimeable number, because it can be changed into a prime (53301481) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52481 + ... + 53486.

It is an arithmetic number, because the mean of its divisors is an integer number (13351968).

Almost surely, 253301401 is an apocalyptic number.

It is an amenable number.

53301401 is a deficient number, since it is larger than the sum of its proper divisors (106471).

53301401 is a wasteful number, since it uses less digits than its factorization.

53301401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 106470.

The product of its (nonzero) digits is 180, while the sum is 17.

The square root of 53301401 is about 7300.7808486490. The cubic root of 53301401 is about 376.3392728641.

Adding to 53301401 its reverse (10410335), we get a palindrome (63711736).

The spelling of 53301401 in words is "fifty-three million, three hundred one thousand, four hundred one".

Divisors: 1 503 105967 53301401