Base | Representation |
---|---|
bin | 1111100000110110100… |
… | …00101110011101011101 |
3 | 1212221212000012221100211 |
4 | 13300123100232131131 |
5 | 32213123012023031 |
6 | 1044512213452421 |
7 | 53340030261556 |
oct | 7603320563535 |
9 | 1787760187324 |
10 | 533033314141 |
11 | 196070456319 |
12 | 8737b941111 |
13 | 3b359a8c9c3 |
14 | 1bb2846732d |
15 | dceabd1bb1 |
hex | 7c1b42e75d |
533033314141 has 2 divisors, whose sum is σ = 533033314142. Its totient is φ = 533033314140.
The previous prime is 533033314123. The next prime is 533033314153. The reversal of 533033314141 is 141413330335.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 492563945241 + 40469368900 = 701829^2 + 201170^2 .
It is a cyclic number.
It is not a de Polignac number, because 533033314141 - 27 = 533033314013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (533033314171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 266516657070 + 266516657071.
It is an arithmetic number, because the mean of its divisors is an integer number (266516657071).
Almost surely, 2533033314141 is an apocalyptic number.
It is an amenable number.
533033314141 is a deficient number, since it is larger than the sum of its proper divisors (1).
533033314141 is an equidigital number, since it uses as much as digits as its factorization.
533033314141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19440, while the sum is 31.
Adding to 533033314141 its reverse (141413330335), we get a palindrome (674446644476).
The spelling of 533033314141 in words is "five hundred thirty-three billion, thirty-three million, three hundred fourteen thousand, one hundred forty-one".
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