Base | Representation |
---|---|
bin | 100110110010010001011… |
… | …1011001011101001111101 |
3 | 200212121022111021101222011 |
4 | 1031210202323023221331 |
5 | 1144314122412311132 |
6 | 15200510134451221 |
7 | 1060061144253424 |
oct | 115444273135175 |
9 | 20777274241864 |
10 | 5330640353917 |
11 | 17757915681aa |
12 | 721144803b11 |
13 | 2c88a5b424b8 |
14 | 14600bdc22bb |
15 | 939ded48b47 |
hex | 4d922ecba7d |
5330640353917 has 2 divisors, whose sum is σ = 5330640353918. Its totient is φ = 5330640353916.
The previous prime is 5330640353903. The next prime is 5330640353923. The reversal of 5330640353917 is 7193530460335.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5256881398521 + 73758955396 = 2292789^2 + 271586^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5330640353917 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5330640353947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2665320176958 + 2665320176959.
It is an arithmetic number, because the mean of its divisors is an integer number (2665320176959).
Almost surely, 25330640353917 is an apocalyptic number.
It is an amenable number.
5330640353917 is a deficient number, since it is larger than the sum of its proper divisors (1).
5330640353917 is an equidigital number, since it uses as much as digits as its factorization.
5330640353917 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3061800, while the sum is 49.
The spelling of 5330640353917 in words is "five trillion, three hundred thirty billion, six hundred forty million, three hundred fifty-three thousand, nine hundred seventeen".
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