Base | Representation |
---|---|
bin | 1001111011100000… |
… | …01010111111110111 |
3 | 111202112020010122121 |
4 | 10331300022333313 |
5 | 41404214133211 |
6 | 2240553540411 |
7 | 246051540613 |
oct | 47560127767 |
9 | 14675203577 |
10 | 5331005431 |
11 | 2296239314 |
12 | 1049414707 |
13 | 66c5c41ab |
14 | 388026343 |
15 | 21303c271 |
hex | 13dc0aff7 |
5331005431 has 2 divisors, whose sum is σ = 5331005432. Its totient is φ = 5331005430.
The previous prime is 5331005419. The next prime is 5331005441. The reversal of 5331005431 is 1345001335.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5331005431 - 229 = 4794134519 is a prime.
It is a super-2 number, since 2×53310054312 = 56839237810702991522, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5331005396 and 5331005405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5331005411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2665502715 + 2665502716.
It is an arithmetic number, because the mean of its divisors is an integer number (2665502716).
Almost surely, 25331005431 is an apocalyptic number.
5331005431 is a deficient number, since it is larger than the sum of its proper divisors (1).
5331005431 is an equidigital number, since it uses as much as digits as its factorization.
5331005431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2700, while the sum is 25.
The square root of 5331005431 is about 73013.7345367295. The cubic root of 5331005431 is about 1746.9066912286.
Adding to 5331005431 its reverse (1345001335), we get a palindrome (6676006766).
The spelling of 5331005431 in words is "five billion, three hundred thirty-one million, five thousand, four hundred thirty-one".
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