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53311010253 = 323248896871
BaseRepresentation
bin110001101001100101…
…010111010111001101
312002121100001220211020
4301221211113113031
51333140104312003
640253555544353
73565045052604
oct615145272715
9162540056736
1053311010253
1120677748066
12a3b98bb0b9
135047a086a7
14281a374a3b
1515c03bed53
hexc699575cd

53311010253 has 24 divisors (see below), whose sum is σ = 74332224960. Its totient is φ = 33983526720.

The previous prime is 53311010251. The next prime is 53311010261. The reversal of 53311010253 is 35201011335.

It is not a de Polignac number, because 53311010253 - 21 = 53311010251 is a prime.

It is a super-2 number, since 2×533110102532 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53311010251) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7755408 + ... + 7762278.

It is an arithmetic number, because the mean of its divisors is an integer number (3097176040).

Almost surely, 253311010253 is an apocalyptic number.

It is an amenable number.

53311010253 is a deficient number, since it is larger than the sum of its proper divisors (21021214707).

53311010253 is a wasteful number, since it uses less digits than its factorization.

53311010253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11809 (or 11786 counting only the distinct ones).

The product of its (nonzero) digits is 1350, while the sum is 24.

Adding to 53311010253 its reverse (35201011335), we get a palindrome (88512021588).

The spelling of 53311010253 in words is "fifty-three billion, three hundred eleven million, ten thousand, two hundred fifty-three".

Divisors: 1 3 23 69 529 1587 4889 6871 14667 20613 112447 158033 337341 474099 2586281 3634759 7758843 10904277 33592319 100776957 772623337 2317870011 17770336751 53311010253