Search a number
-
+
53311323011 = 411300276171
BaseRepresentation
bin110001101001100110…
…100011101110000011
312002121100122210211212
4301221212203232003
51333140144314021
640254010400335
73565050524462
oct615146435603
9162540583755
1053311323011
1120677941041
12a3b9a300ab
135047ab7b5b
14281a4169d9
1515c043285b
hexc699a3b83

53311323011 has 4 divisors (see below), whose sum is σ = 54611599224. Its totient is φ = 52011046800.

The previous prime is 53311323001. The next prime is 53311323017. The reversal of 53311323011 is 11032311335.

53311323011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53311323011 is a prime.

It is a super-2 number, since 2×533113230112 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53311323017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 650138045 + ... + 650138126.

It is an arithmetic number, because the mean of its divisors is an integer number (13652899806).

Almost surely, 253311323011 is an apocalyptic number.

53311323011 is a deficient number, since it is larger than the sum of its proper divisors (1300276213).

53311323011 is a wasteful number, since it uses less digits than its factorization.

53311323011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1300276212.

The product of its (nonzero) digits is 810, while the sum is 23.

Adding to 53311323011 its reverse (11032311335), we get a palindrome (64343634346).

The spelling of 53311323011 in words is "fifty-three billion, three hundred eleven million, three hundred twenty-three thousand, eleven".

Divisors: 1 41 1300276171 53311323011