Base | Representation |
---|---|
bin | 11000001111101001110011… |
… | …11110010011000110101111 |
3 | 20222202210210022122121012001 |
4 | 30013310321332103012233 |
5 | 23442000343312141433 |
6 | 305220144211553131 |
7 | 14141560401016333 |
oct | 1407647176230657 |
9 | 228683708577161 |
10 | 53314401677743 |
11 | 15a95568930778 |
12 | 5b908312bb7a7 |
13 | 23996ac96b78b |
14 | d246061d97c3 |
15 | 626c6b08b57d |
hex | 307d39f931af |
53314401677743 has 4 divisors (see below), whose sum is σ = 53314529935720. Its totient is φ = 53314273419768.
The previous prime is 53314401677717. The next prime is 53314401677851. The reversal of 53314401677743 is 34777610441335.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53314401677743 - 29 = 53314401677231 is a prime.
It is a super-2 number, since 2×533144016777432 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53314401627743) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63503433 + ... + 64337506.
It is an arithmetic number, because the mean of its divisors is an integer number (13328632483930).
Almost surely, 253314401677743 is an apocalyptic number.
53314401677743 is a deficient number, since it is larger than the sum of its proper divisors (128257977).
53314401677743 is a wasteful number, since it uses less digits than its factorization.
53314401677743 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 128257976.
The product of its (nonzero) digits is 17781120, while the sum is 55.
The spelling of 53314401677743 in words is "fifty-three trillion, three hundred fourteen billion, four hundred one million, six hundred seventy-seven thousand, seven hundred forty-three".
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