Base | Representation |
---|---|
bin | 110001101010001000… |
… | …000111011011110101 |
3 | 12002121222012202010020 |
4 | 301222020013123311 |
5 | 1333144422320203 |
6 | 40254523115353 |
7 | 3565215354024 |
oct | 615210073365 |
9 | 162558182106 |
10 | 53320120053 |
11 | 206818aa422 |
12 | a400972b59 |
13 | 5049877cc5 |
14 | 281b6668bb |
15 | 15c10be153 |
hex | c6a2076f5 |
53320120053 has 32 divisors (see below), whose sum is σ = 74896036992. Its totient is φ = 33706982400.
The previous prime is 53320120039. The next prime is 53320120057. The reversal of 53320120053 is 35002102335.
It is a happy number.
53320120053 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53320120053 - 26 = 53320119989 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53320120057) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 659313 + ... + 735753.
It is an arithmetic number, because the mean of its divisors is an integer number (2340501156).
Almost surely, 253320120053 is an apocalyptic number.
53320120053 is a gapful number since it is divisible by the number (53) formed by its first and last digit.
It is an amenable number.
53320120053 is a deficient number, since it is larger than the sum of its proper divisors (21575916939).
53320120053 is a wasteful number, since it uses less digits than its factorization.
53320120053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 76645.
The product of its (nonzero) digits is 2700, while the sum is 24.
Adding to 53320120053 its reverse (35002102335), we get a palindrome (88322222388).
The spelling of 53320120053 in words is "fifty-three billion, three hundred twenty million, one hundred twenty thousand, fifty-three".
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