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533204335141 is a prime number
BaseRepresentation
bin1111100001001010111…
…01000111101000100101
31212222021221000201001221
413300211131013220211
532214000302211031
61044541203220341
753344205032222
oct7604535075045
91788257021057
10533204335141
11196148a45995
12874090776b1
133b38633b96a
141bb43064949
15dd0ac14a11
hex7c25747a25

533204335141 has 2 divisors, whose sum is σ = 533204335142. Its totient is φ = 533204335140.

The previous prime is 533204335091. The next prime is 533204335187. The reversal of 533204335141 is 141533402335.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 475657123041 + 57547212100 = 689679^2 + 239890^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-533204335141 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 533204335097 and 533204335106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (533204339141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 266602167570 + 266602167571.

It is an arithmetic number, because the mean of its divisors is an integer number (266602167571).

Almost surely, 2533204335141 is an apocalyptic number.

It is an amenable number.

533204335141 is a deficient number, since it is larger than the sum of its proper divisors (1).

533204335141 is an equidigital number, since it uses as much as digits as its factorization.

533204335141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64800, while the sum is 34.

Adding to 533204335141 its reverse (141533402335), we get a palindrome (674737737476).

The spelling of 533204335141 in words is "five hundred thirty-three billion, two hundred four million, three hundred thirty-five thousand, one hundred forty-one".