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53321243404301 = 165311322551091
BaseRepresentation
bin11000001111110110100011…
…10001011010100000001101
320222210110110010120022121222
430013323101301122200031
523442103401302414201
6305223235133533125
714142222055520105
oct1407732161324015
9228713403508558
1053321243404301
1115a98459902144
125b920206441a5
13239a230239aa2
14d24a94b16205
1562701ba3e91b
hex307ed1c5a80d

53321243404301 has 4 divisors (see below), whose sum is σ = 53321566120704. Its totient is φ = 53320920687900.

The previous prime is 53321243404291. The next prime is 53321243404321. The reversal of 53321243404301 is 10340434212335.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53321243404301 - 218 = 53321243142157 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53321243404321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 161110235 + ... + 161440856.

It is an arithmetic number, because the mean of its divisors is an integer number (13330391530176).

Almost surely, 253321243404301 is an apocalyptic number.

It is an amenable number.

53321243404301 is a deficient number, since it is larger than the sum of its proper divisors (322716403).

53321243404301 is a wasteful number, since it uses less digits than its factorization.

53321243404301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 322716402.

The product of its (nonzero) digits is 103680, while the sum is 35.

Adding to 53321243404301 its reverse (10340434212335), we get a palindrome (63661677616636).

The spelling of 53321243404301 in words is "fifty-three trillion, three hundred twenty-one billion, two hundred forty-three million, four hundred four thousand, three hundred one".

Divisors: 1 165311 322551091 53321243404301