Base | Representation |
---|---|
bin | 100110110010111111111… |
… | …1001100100101111111001 |
3 | 200212202100012102111001012 |
4 | 1031211333321210233321 |
5 | 1144330321223312442 |
6 | 15201325020003305 |
7 | 1060144614662123 |
oct | 115457771445771 |
9 | 20782305374035 |
10 | 5332200213497 |
11 | 1776412012853 |
12 | 7214bb090535 |
13 | 2c8a94062831 |
14 | 146119228213 |
15 | 93a81c69582 |
hex | 4d97fe64bf9 |
5332200213497 has 2 divisors, whose sum is σ = 5332200213498. Its totient is φ = 5332200213496.
The previous prime is 5332200213451. The next prime is 5332200213553. The reversal of 5332200213497 is 7943120022335.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5150339758096 + 181860455401 = 2269436^2 + 426451^2 .
It is a cyclic number.
It is not a de Polignac number, because 5332200213497 - 230 = 5331126471673 is a prime.
It is not a weakly prime, because it can be changed into another prime (5332200213797) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2666100106748 + 2666100106749.
It is an arithmetic number, because the mean of its divisors is an integer number (2666100106749).
Almost surely, 25332200213497 is an apocalyptic number.
It is an amenable number.
5332200213497 is a deficient number, since it is larger than the sum of its proper divisors (1).
5332200213497 is an equidigital number, since it uses as much as digits as its factorization.
5332200213497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 272160, while the sum is 41.
The spelling of 5332200213497 in words is "five trillion, three hundred thirty-two billion, two hundred million, two hundred thirteen thousand, four hundred ninety-seven".
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