Base | Representation |
---|---|
bin | 110001101011011100… |
… | …000111011001101101 |
3 | 12002200111122110211022 |
4 | 301223130013121231 |
5 | 1333221041440023 |
6 | 40301031103525 |
7 | 3565603465121 |
oct | 615334073155 |
9 | 162614573738 |
10 | 53342140013 |
11 | 2069327a338 |
12 | a408211ba5 |
13 | 50512b7976 |
14 | 2820559581 |
15 | 15c2ebd7c8 |
hex | c6b70766d |
53342140013 has 2 divisors, whose sum is σ = 53342140014. Its totient is φ = 53342140012.
The previous prime is 53342139967. The next prime is 53342140021. The reversal of 53342140013 is 31004124335.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31082395204 + 22259744809 = 176302^2 + 149197^2 .
It is a cyclic number.
It is not a de Polignac number, because 53342140013 - 226 = 53275031149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53342140043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26671070006 + 26671070007.
It is an arithmetic number, because the mean of its divisors is an integer number (26671070007).
Almost surely, 253342140013 is an apocalyptic number.
It is an amenable number.
53342140013 is a deficient number, since it is larger than the sum of its proper divisors (1).
53342140013 is an equidigital number, since it uses as much as digits as its factorization.
53342140013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 26.
Adding to 53342140013 its reverse (31004124335), we get a palindrome (84346264348).
The spelling of 53342140013 in words is "fifty-three billion, three hundred forty-two million, one hundred forty thousand, thirteen".
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