Base | Representation |
---|---|
bin | 100110110100000001110… |
… | …1101001000011010000001 |
3 | 200212222001022102201111002 |
4 | 1031220003231020122001 |
5 | 1144344333323403233 |
6 | 15202332252301345 |
7 | 1060253455662314 |
oct | 115500355103201 |
9 | 20788038381432 |
10 | 5334411544193 |
11 | 1777347281286 |
12 | 721a17771855 |
13 | 2c9057230634 |
14 | 146288bb497b |
15 | 93b60e736e8 |
hex | 4da03b48681 |
5334411544193 has 2 divisors, whose sum is σ = 5334411544194. Its totient is φ = 5334411544192.
The previous prime is 5334411544141. The next prime is 5334411544237. The reversal of 5334411544193 is 3914451144335.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4036334137969 + 1298077406224 = 2009063^2 + 1139332^2 .
It is a cyclic number.
It is not a de Polignac number, because 5334411544193 - 210 = 5334411543169 is a prime.
It is not a weakly prime, because it can be changed into another prime (5334411544793) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2667205772096 + 2667205772097.
It is an arithmetic number, because the mean of its divisors is an integer number (2667205772097).
Almost surely, 25334411544193 is an apocalyptic number.
It is an amenable number.
5334411544193 is a deficient number, since it is larger than the sum of its proper divisors (1).
5334411544193 is an equidigital number, since it uses as much as digits as its factorization.
5334411544193 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1555200, while the sum is 47.
The spelling of 5334411544193 in words is "five trillion, three hundred thirty-four billion, four hundred eleven million, five hundred forty-four thousand, one hundred ninety-three".
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