Base | Representation |
---|---|
bin | 100110110100011101001… |
… | …1110010010110010101111 |
3 | 200220001102100102111200112 |
4 | 1031220322132102302233 |
5 | 1144403224040321310 |
6 | 15203003354450235 |
7 | 1060315314100415 |
oct | 115507236226257 |
9 | 20801370374615 |
10 | 5335330401455 |
11 | 1777778a1334a |
12 | 72203343397b |
13 | 2c91726ca262 |
14 | 146334c3d2b5 |
15 | 93bb6977705 |
hex | 4da3a792caf |
5335330401455 has 48 divisors (see below), whose sum is σ = 6860119845600. Its totient is φ = 3978582854400.
The previous prime is 5335330401421. The next prime is 5335330401469. The reversal of 5335330401455 is 5541040335335.
It is not a de Polignac number, because 5335330401455 - 212 = 5335330397359 is a prime.
It is a super-2 number, since 2×53353304014552 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 58339865 + ... + 58431245.
It is an arithmetic number, because the mean of its divisors is an integer number (142919163450).
Almost surely, 25335330401455 is an apocalyptic number.
5335330401455 is a deficient number, since it is larger than the sum of its proper divisors (1524789444145).
5335330401455 is a wasteful number, since it uses less digits than its factorization.
5335330401455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 91896 (or 91865 counting only the distinct ones).
The product of its (nonzero) digits is 810000, while the sum is 41.
The spelling of 5335330401455 in words is "five trillion, three hundred thirty-five billion, three hundred thirty million, four hundred one thousand, four hundred fifty-five".
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