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5335333130132 = 221333833282533
BaseRepresentation
bin100110110100011101010…
…1000101100111110010100
3200220001102112120010201122
41031220322220230332110
51144403230240131012
615203003533143112
71060315346223635
oct115507250547624
920801375503648
105335333130132
11177777a507455
1272203432aa98
132c9173144265
1414633534d88c
1593bb6d15e72
hex4da3aa2cf94

5335333130132 has 6 divisors (see below), whose sum is σ = 9336832977738. Its totient is φ = 2667666565064.

The previous prime is 5335333130129. The next prime is 5335333130167. The reversal of 5335333130132 is 2310313335335.

It can be written as a sum of positive squares in only one way, i.e., 4481028520336 + 854304609796 = 2116844^2 + 924286^2 .

It is a junction number, because it is equal to n+sod(n) for n = 5335333130092 and 5335333130101.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666916641263 + ... + 666916641270.

It is an arithmetic number, because the mean of its divisors is an integer number (1556138829623).

Almost surely, 25335333130132 is an apocalyptic number.

It is an amenable number.

5335333130132 is a deficient number, since it is larger than the sum of its proper divisors (4001499847606).

5335333130132 is a wasteful number, since it uses less digits than its factorization.

5335333130132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1333833282537 (or 1333833282535 counting only the distinct ones).

The product of its (nonzero) digits is 109350, while the sum is 35.

Adding to 5335333130132 its reverse (2310313335335), we get a palindrome (7645646465467).

The spelling of 5335333130132 in words is "five trillion, three hundred thirty-five billion, three hundred thirty-three million, one hundred thirty thousand, one hundred thirty-two".

Divisors: 1 2 4 1333833282533 2667666565066 5335333130132