Base | Representation |
---|---|
bin | 100110110100011101010… |
… | …1000101100111110010100 |
3 | 200220001102112120010201122 |
4 | 1031220322220230332110 |
5 | 1144403230240131012 |
6 | 15203003533143112 |
7 | 1060315346223635 |
oct | 115507250547624 |
9 | 20801375503648 |
10 | 5335333130132 |
11 | 177777a507455 |
12 | 72203432aa98 |
13 | 2c9173144265 |
14 | 14633534d88c |
15 | 93bb6d15e72 |
hex | 4da3aa2cf94 |
5335333130132 has 6 divisors (see below), whose sum is σ = 9336832977738. Its totient is φ = 2667666565064.
The previous prime is 5335333130129. The next prime is 5335333130167. The reversal of 5335333130132 is 2310313335335.
It can be written as a sum of positive squares in only one way, i.e., 4481028520336 + 854304609796 = 2116844^2 + 924286^2 .
It is a junction number, because it is equal to n+sod(n) for n = 5335333130092 and 5335333130101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666916641263 + ... + 666916641270.
It is an arithmetic number, because the mean of its divisors is an integer number (1556138829623).
Almost surely, 25335333130132 is an apocalyptic number.
It is an amenable number.
5335333130132 is a deficient number, since it is larger than the sum of its proper divisors (4001499847606).
5335333130132 is a wasteful number, since it uses less digits than its factorization.
5335333130132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1333833282537 (or 1333833282535 counting only the distinct ones).
The product of its (nonzero) digits is 109350, while the sum is 35.
Adding to 5335333130132 its reverse (2310313335335), we get a palindrome (7645646465467).
The spelling of 5335333130132 in words is "five trillion, three hundred thirty-five billion, three hundred thirty-three million, one hundred thirty thousand, one hundred thirty-two".
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