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5335410135337 is a prime number
BaseRepresentation
bin100110110100011111100…
…1110011101000100101001
3200220001121220110102000021
41031220333032131010221
51144403404443312322
615203015323440441
71060320302604622
oct115507716350451
920801556412007
105335410135337
111777809a22617
12722056086121
132c9186096479
14146341676a49
1593bbd9774c7
hex4da3f39d129

5335410135337 has 2 divisors, whose sum is σ = 5335410135338. Its totient is φ = 5335410135336.

The previous prime is 5335410135311. The next prime is 5335410135397. The reversal of 5335410135337 is 7335310145335.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4285309869801 + 1050100265536 = 2070099^2 + 1024744^2 .

It is a cyclic number.

It is not a de Polignac number, because 5335410135337 - 211 = 5335410133289 is a prime.

It is a super-2 number, since 2×53354101353372 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5335410135293 and 5335410135302.

It is not a weakly prime, because it can be changed into another prime (5335410135397) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2667705067668 + 2667705067669.

It is an arithmetic number, because the mean of its divisors is an integer number (2667705067669).

Almost surely, 25335410135337 is an apocalyptic number.

It is an amenable number.

5335410135337 is a deficient number, since it is larger than the sum of its proper divisors (1).

5335410135337 is an equidigital number, since it uses as much as digits as its factorization.

5335410135337 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 850500, while the sum is 43.

The spelling of 5335410135337 in words is "five trillion, three hundred thirty-five billion, four hundred ten million, one hundred thirty-five thousand, three hundred thirty-seven".