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5335433030143 = 103199764934031
BaseRepresentation
bin100110110100100000010…
…0101110010100111111111
3200220001200111112120210001
41031221000211302213333
51144403431323431033
615203021502255131
71060321001321416
oct115510045624777
920801614476701
105335433030143
11177782093a847
127220618874a7
132c918aa513a8
1414634471647d
1593bc099ae7d
hex4da409729ff

5335433030143 has 16 divisors (see below), whose sum is σ = 5415171840000. Its totient is φ = 5256240042240.

The previous prime is 5335433030099. The next prime is 5335433030219. The reversal of 5335433030143 is 3410303345335.

It is a cyclic number.

It is not a de Polignac number, because 5335433030143 - 213 = 5335433021951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5335433030443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 156764538 + ... + 156798568.

It is an arithmetic number, because the mean of its divisors is an integer number (338448240000).

Almost surely, 25335433030143 is an apocalyptic number.

5335433030143 is a deficient number, since it is larger than the sum of its proper divisors (79738809857).

5335433030143 is a wasteful number, since it uses less digits than its factorization.

5335433030143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41982.

The product of its (nonzero) digits is 291600, while the sum is 37.

Adding to 5335433030143 its reverse (3410303345335), we get a palindrome (8745736375478).

The spelling of 5335433030143 in words is "five trillion, three hundred thirty-five billion, four hundred thirty-three million, thirty thousand, one hundred forty-three".

Divisors: 1 103 199 7649 20497 34031 787847 1522151 3505193 6772169 156781553 260303119 697533407 26811221257 51800320681 5335433030143