Base | Representation |
---|---|
bin | 100110110100100000100… |
… | …1111110010101010001111 |
3 | 200220001201021020221220221 |
4 | 1031221001033302222033 |
5 | 1144403442133242320 |
6 | 15203022534252211 |
7 | 1060321164026203 |
oct | 115510117625217 |
9 | 20801637227827 |
10 | 5335444040335 |
11 | 177782707a982 |
12 | 7220654b7067 |
13 | 2c91901079b6 |
14 | 146345d80b03 |
15 | 93bc19233aa |
hex | 4da413f2a8f |
5335444040335 has 16 divisors (see below), whose sum is σ = 6442134764832. Its totient is φ = 4242035318400.
The previous prime is 5335444040321. The next prime is 5335444040357. The reversal of 5335444040335 is 5330404445335.
It is not a de Polignac number, because 5335444040335 - 223 = 5335435651727 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5335444040291 and 5335444040300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4560276 + ... + 5609545.
It is an arithmetic number, because the mean of its divisors is an integer number (402633422802).
Almost surely, 25335444040335 is an apocalyptic number.
5335444040335 is a deficient number, since it is larger than the sum of its proper divisors (1106690724497).
5335444040335 is a wasteful number, since it uses less digits than its factorization.
5335444040335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10170474.
The product of its (nonzero) digits is 2592000, while the sum is 43.
The spelling of 5335444040335 in words is "five trillion, three hundred thirty-five billion, four hundred forty-four million, forty thousand, three hundred thirty-five".
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