Base | Representation |
---|---|
bin | 100110110100100011110… |
… | …1001010110100100111111 |
3 | 200220001222202021121122222 |
4 | 1031221013221112210333 |
5 | 1144404202124414401 |
6 | 15203041331355555 |
7 | 1060323636431630 |
oct | 115510751264477 |
9 | 20801882247588 |
10 | 5335551404351 |
11 | 1777881741073 |
12 | 722095452bbb |
13 | 2c91a94292bc |
14 | 14635632b887 |
15 | 93bcb07ec1b |
hex | 4da47a5693f |
5335551404351 has 4 divisors (see below), whose sum is σ = 6097773033552. Its totient is φ = 4573329775152.
The previous prime is 5335551404231. The next prime is 5335551404377. The reversal of 5335551404351 is 1534041555335.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5335551404351 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5335554404351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 381110814590 + ... + 381110814603.
It is an arithmetic number, because the mean of its divisors is an integer number (1524443258388).
Almost surely, 25335551404351 is an apocalyptic number.
5335551404351 is a deficient number, since it is larger than the sum of its proper divisors (762221629201).
5335551404351 is an equidigital number, since it uses as much as digits as its factorization.
5335551404351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 762221629200.
The product of its (nonzero) digits is 1350000, while the sum is 44.
Adding to 5335551404351 its reverse (1534041555335), we get a palindrome (6869592959686).
The spelling of 5335551404351 in words is "five trillion, three hundred thirty-five billion, five hundred fifty-one million, four hundred four thousand, three hundred fifty-one".
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