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53400041 = 103518447
BaseRepresentation
bin1100101110110…
…1000111101001
310201111000002022
43023231013221
5102132300131
65144314225
71215615152
oct313550751
9121430068
1053400041
1128163272
1215a72975
13b0a8b76
147140929
154a4c37b
hex32ed1e9

53400041 has 4 divisors (see below), whose sum is σ = 53918592. Its totient is φ = 52881492.

The previous prime is 53400001. The next prime is 53400059. The reversal of 53400041 is 14000435.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53400041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53399992 and 53400019.

It is not an unprimeable number, because it can be changed into a prime (53400001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 259121 + ... + 259326.

It is an arithmetic number, because the mean of its divisors is an integer number (13479648).

Almost surely, 253400041 is an apocalyptic number.

It is an amenable number.

53400041 is a deficient number, since it is larger than the sum of its proper divisors (518551).

53400041 is a wasteful number, since it uses less digits than its factorization.

53400041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 518550.

The product of its (nonzero) digits is 240, while the sum is 17.

The square root of 53400041 is about 7307.5331679028. The cubic root of 53400041 is about 376.5712819620.

Adding to 53400041 its reverse (14000435), we get a palindrome (67400476).

The spelling of 53400041 in words is "fifty-three million, four hundred thousand, forty-one".

Divisors: 1 103 518447 53400041