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534004052541 = 3444140081367
BaseRepresentation
bin1111100010101010001…
…11110011001000111101
31220001100122211120002220
413301111013303020331
532222120014140131
61045152412035553
753403055360641
oct7612507631075
91801318746086
10534004052541
11196519403463
12875b0a62bb9
133b482c2301b
141bbbb358c21
15dd56032e96
hex7c551f323d

534004052541 has 8 divisors (see below), whose sum is σ = 712165746624. Its totient is φ = 355922530080.

The previous prime is 534004052539. The next prime is 534004052579. The reversal of 534004052541 is 145250400435.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 534004052541 - 21 = 534004052539 is a prime.

It is a super-2 number, since 2×5340040525412 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (534004052521) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20027361 + ... + 20054006.

It is an arithmetic number, because the mean of its divisors is an integer number (89020718328).

Almost surely, 2534004052541 is an apocalyptic number.

It is an amenable number.

534004052541 is a deficient number, since it is larger than the sum of its proper divisors (178161694083).

534004052541 is a wasteful number, since it uses less digits than its factorization.

534004052541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40085811.

The product of its (nonzero) digits is 48000, while the sum is 33.

Adding to 534004052541 its reverse (145250400435), we get a palindrome (679254452976).

The spelling of 534004052541 in words is "five hundred thirty-four billion, four million, fifty-two thousand, five hundred forty-one".

Divisors: 1 3 4441 13323 40081367 120244101 178001350847 534004052541