Base | Representation |
---|---|
bin | 11000010010001010000010… |
… | …10111111111100101101111 |
3 | 21000002000211110002022022022 |
4 | 30021011001113333211233 |
5 | 23444403032322344413 |
6 | 305323452222340355 |
7 | 14151024213625301 |
oct | 1411050127774557 |
9 | 230060743068268 |
10 | 53400425199983 |
11 | 16018aa1974204 |
12 | 5ba543a42a6bb |
13 | 23a483b9b6a24 |
14 | d28846d47971 |
15 | 62910328c608 |
hex | 3091415ff96f |
53400425199983 has 2 divisors, whose sum is σ = 53400425199984. Its totient is φ = 53400425199982.
The previous prime is 53400425199937. The next prime is 53400425200147. The reversal of 53400425199983 is 38999152400435.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53400425199983 - 216 = 53400425134447 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53400425199923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26700212599991 + 26700212599992.
It is an arithmetic number, because the mean of its divisors is an integer number (26700212599992).
Almost surely, 253400425199983 is an apocalyptic number.
53400425199983 is a deficient number, since it is larger than the sum of its proper divisors (1).
53400425199983 is an equidigital number, since it uses as much as digits as its factorization.
53400425199983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41990400, while the sum is 62.
The spelling of 53400425199983 in words is "fifty-three trillion, four hundred billion, four hundred twenty-five million, one hundred ninety-nine thousand, nine hundred eighty-three".
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