Base | Representation |
---|---|
bin | 111100101101100110101011… |
… | …1111001011101111101001111 |
3 | 2121000212002120202222121122011 |
4 | 1321123031113321131331033 |
5 | 1024444100412301100142 |
6 | 5131443321354002051 |
7 | 220325432551046203 |
oct | 17133152771357517 |
9 | 2530762522877564 |
10 | 534033413300047 |
11 | 145183331649351 |
12 | 4ba8b305716327 |
13 | 19bca19a19520b |
14 | 95c34d8620b03 |
15 | 41b167bc8e417 |
hex | 1e5b357e5df4f |
534033413300047 has 2 divisors, whose sum is σ = 534033413300048. Its totient is φ = 534033413300046.
The previous prime is 534033413300011. The next prime is 534033413300063. The reversal of 534033413300047 is 740003314330435.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 534033413300047 - 235 = 533999053561679 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 534033413299982 and 534033413300009.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (534033413300087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267016706650023 + 267016706650024.
It is an arithmetic number, because the mean of its divisors is an integer number (267016706650024).
Almost surely, 2534033413300047 is an apocalyptic number.
534033413300047 is a deficient number, since it is larger than the sum of its proper divisors (1).
534033413300047 is an equidigital number, since it uses as much as digits as its factorization.
534033413300047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 544320, while the sum is 40.
The spelling of 534033413300047 in words is "five hundred thirty-four trillion, thirty-three billion, four hundred thirteen million, three hundred thousand, forty-seven".
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