Base | Representation |
---|---|
bin | 100110110110110100011… |
… | …0100111000111100011001 |
3 | 200220112111212111110020211 |
4 | 1031231220310320330121 |
5 | 1144444121134402441 |
6 | 15205203003051121 |
7 | 1060555110616165 |
oct | 115555064707431 |
9 | 20815455443224 |
10 | 5340403044121 |
11 | 1779941326912 |
12 | 72300a210aa1 |
13 | 2c97a0611472 |
14 | 14669680dca5 |
15 | 93db1e7ca81 |
hex | 4db68d38f19 |
5340403044121 has 2 divisors, whose sum is σ = 5340403044122. Its totient is φ = 5340403044120.
The previous prime is 5340403044079. The next prime is 5340403044139. The reversal of 5340403044121 is 1214403040435.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3552606746896 + 1787796297225 = 1884836^2 + 1337085^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5340403044121 is a prime.
It is not a weakly prime, because it can be changed into another prime (5340403045121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2670201522060 + 2670201522061.
It is an arithmetic number, because the mean of its divisors is an integer number (2670201522061).
Almost surely, 25340403044121 is an apocalyptic number.
It is an amenable number.
5340403044121 is a deficient number, since it is larger than the sum of its proper divisors (1).
5340403044121 is an equidigital number, since it uses as much as digits as its factorization.
5340403044121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 5340403044121 its reverse (1214403040435), we get a palindrome (6554806084556).
The spelling of 5340403044121 in words is "five trillion, three hundred forty billion, four hundred three million, forty-four thousand, one hundred twenty-one".
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