Base | Representation |
---|---|
bin | 100110110110111000000… |
… | …0010101011111010110111 |
3 | 200220112211022021210111011 |
4 | 1031231300002223322313 |
5 | 1144444343132220203 |
6 | 15205223005453051 |
7 | 1060561110602446 |
oct | 115556002537267 |
9 | 20815738253434 |
10 | 5340524101303 |
11 | 17799a369a976 |
12 | 723042871187 |
13 | 2c97bc718631 |
14 | 1466a8922d5d |
15 | 93dbc8e176d |
hex | 4db700abeb7 |
5340524101303 has 4 divisors (see below), whose sum is σ = 5340586080160. Its totient is φ = 5340462122448.
The previous prime is 5340524101267. The next prime is 5340524101309. The reversal of 5340524101303 is 3031014250435.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5340524101303 - 221 = 5340522004151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5340524101309) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30859998 + ... + 31032571.
It is an arithmetic number, because the mean of its divisors is an integer number (1335146520040).
Almost surely, 25340524101303 is an apocalyptic number.
5340524101303 is a deficient number, since it is larger than the sum of its proper divisors (61978857).
5340524101303 is an equidigital number, since it uses as much as digits as its factorization.
5340524101303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61978856.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 5340524101303 its reverse (3031014250435), we get a palindrome (8371538351738).
The spelling of 5340524101303 in words is "five trillion, three hundred forty billion, five hundred twenty-four million, one hundred one thousand, three hundred three".
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