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534124442231503 is a prime number
BaseRepresentation
bin111100101110010001000100…
…1101001010010001011001111
32121001011210112201222110100221
41321130202021221102023033
51030002043324202402003
65131553214211532211
7220335134413152004
oct17134421151221317
92531153481873327
10534124442231503
111452089a4053912
124baa4a8abba067
1319c05946214176
1495c7a9203b8ab
1541b3c086147bd
hex1e5c889a522cf

534124442231503 has 2 divisors, whose sum is σ = 534124442231504. Its totient is φ = 534124442231502.

The previous prime is 534124442231461. The next prime is 534124442231561. The reversal of 534124442231503 is 305132244421435.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 534124442231503 - 29 = 534124442230991 is a prime.

It is a super-2 number, since 2×5341244422315032 (a number of 30 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 534124442231503.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (534124442231573) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267062221115751 + 267062221115752.

It is an arithmetic number, because the mean of its divisors is an integer number (267062221115752).

Almost surely, 2534124442231503 is an apocalyptic number.

534124442231503 is a deficient number, since it is larger than the sum of its proper divisors (1).

534124442231503 is an equidigital number, since it uses as much as digits as its factorization.

534124442231503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1382400, while the sum is 43.

Adding to 534124442231503 its reverse (305132244421435), we get a palindrome (839256686652938).

The spelling of 534124442231503 in words is "five hundred thirty-four trillion, one hundred twenty-four billion, four hundred forty-two million, two hundred thirty-one thousand, five hundred three".