Base | Representation |
---|---|
bin | 100110110111010110101… |
… | …0001001000110111010111 |
3 | 200220122110220010220021101 |
4 | 1031232231101020313113 |
5 | 1200003444113100210 |
6 | 15205512542130531 |
7 | 1060625422624135 |
oct | 115565521106727 |
9 | 20818426126241 |
10 | 5341551300055 |
11 | 177a380500563 |
12 | 72328a880a47 |
13 | 2c9924489749 |
14 | 146765110755 |
15 | 93e2cb96a3a |
hex | 4dbad448dd7 |
5341551300055 has 32 divisors (see below), whose sum is σ = 6551266549248. Its totient is φ = 4179785500800.
The previous prime is 5341551300053. The next prime is 5341551300073. The reversal of 5341551300055 is 5500031551435.
It is not a de Polignac number, because 5341551300055 - 21 = 5341551300053 is a prime.
It is a super-2 number, since 2×53415513000552 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5341551299987 and 5341551300023.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5341551300053) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 78672232 + ... + 78740098.
It is an arithmetic number, because the mean of its divisors is an integer number (204727079664).
Almost surely, 25341551300055 is an apocalyptic number.
5341551300055 is a deficient number, since it is larger than the sum of its proper divisors (1209715249193).
5341551300055 is a wasteful number, since it uses less digits than its factorization.
5341551300055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 69367.
The product of its (nonzero) digits is 112500, while the sum is 37.
The spelling of 5341551300055 in words is "five trillion, three hundred forty-one billion, five hundred fifty-one million, three hundred thousand, fifty-five".
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