Search a number
-
+
53415524404919 is a prime number
BaseRepresentation
bin11000010010100110001010…
…10110111000111010110111
321000010110210201220101120202
430021103011112320322313
524000124443221424134
6305334430402551115
714152100330016035
oct1411230526707267
9230113721811522
1053415524404919
111602443aa94376
125ba835306849b
1323a60a6c58711
14d2947a3d3555
156296d8b4ad7e
hex3094c55b8eb7

53415524404919 has 2 divisors, whose sum is σ = 53415524404920. Its totient is φ = 53415524404918.

The previous prime is 53415524404789. The next prime is 53415524404939. The reversal of 53415524404919 is 91940442551435.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53415524404919 is a prime.

It is a super-3 number, since 3×534155244049193 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53415524404939) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26707762202459 + 26707762202460.

It is an arithmetic number, because the mean of its divisors is an integer number (26707762202460).

Almost surely, 253415524404919 is an apocalyptic number.

53415524404919 is a deficient number, since it is larger than the sum of its proper divisors (1).

53415524404919 is an equidigital number, since it uses as much as digits as its factorization.

53415524404919 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552000, while the sum is 56.

The spelling of 53415524404919 in words is "fifty-three trillion, four hundred fifteen billion, five hundred twenty-four million, four hundred four thousand, nine hundred nineteen".