Base | Representation |
---|---|
bin | 11000010010101111001010… |
… | …10010111010100111111101 |
3 | 21000010221021101220021201212 |
4 | 30021113211102322213331 |
5 | 24000214341412422113 |
6 | 305340550011414205 |
7 | 14152331126063135 |
oct | 1411274522724775 |
9 | 230127241807655 |
10 | 53420355201533 |
11 | 16026499933371 |
12 | 5ba9280a54365 |
13 | 23a6696a23758 |
14 | d297b7c0bac5 |
15 | 6298bcccd0a8 |
hex | 3095e54ba9fd |
53420355201533 has 2 divisors, whose sum is σ = 53420355201534. Its totient is φ = 53420355201532.
The previous prime is 53420355201529. The next prime is 53420355201557. The reversal of 53420355201533 is 33510255302435.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 31896944516644 + 21523410684889 = 5647738^2 + 4639333^2 .
It is a cyclic number.
It is not a de Polignac number, because 53420355201533 - 22 = 53420355201529 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53420355201833) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26710177600766 + 26710177600767.
It is an arithmetic number, because the mean of its divisors is an integer number (26710177600767).
Almost surely, 253420355201533 is an apocalyptic number.
It is an amenable number.
53420355201533 is a deficient number, since it is larger than the sum of its proper divisors (1).
53420355201533 is an equidigital number, since it uses as much as digits as its factorization.
53420355201533 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 810000, while the sum is 41.
The spelling of 53420355201533 in words is "fifty-three trillion, four hundred twenty billion, three hundred fifty-five million, two hundred one thousand, five hundred thirty-three".
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