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53421050123151 = 317807016707717
BaseRepresentation
bin11000010010110000011101…
…01101110101001110001111
321000011000001211111221222120
430021120032231311032033
524000222302312420101
6305341142554144023
714152354264603524
oct1411301655651617
9230130054457876
1053421050123151
1116026816124257
125ba9435722013
1323a67779a5489
14d2984222314b
1562990dceab36
hex30960eb7538f

53421050123151 has 4 divisors (see below), whose sum is σ = 71228066830872. Its totient is φ = 35614033415432.

The previous prime is 53421050123113. The next prime is 53421050123201. The reversal of 53421050123151 is 15132105012435.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53421050123151 - 210 = 53421050122127 is a prime.

It is a super-2 number, since 2×534210501231512 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53421050123851) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8903508353856 + ... + 8903508353861.

It is an arithmetic number, because the mean of its divisors is an integer number (17807016707718).

Almost surely, 253421050123151 is an apocalyptic number.

53421050123151 is a deficient number, since it is larger than the sum of its proper divisors (17807016707721).

53421050123151 is a wasteful number, since it uses less digits than its factorization.

53421050123151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17807016707720.

The product of its (nonzero) digits is 18000, while the sum is 33.

Adding to 53421050123151 its reverse (15132105012435), we get a palindrome (68553155135586).

The spelling of 53421050123151 in words is "fifty-three trillion, four hundred twenty-one billion, fifty million, one hundred twenty-three thousand, one hundred fifty-one".

Divisors: 1 3 17807016707717 53421050123151