Base | Representation |
---|---|
bin | 110001110000001110… |
… | …011010001101011101 |
3 | 12002220002201210020222 |
4 | 301300032122031131 |
5 | 1333402120324432 |
6 | 40313020051125 |
7 | 3600600121604 |
oct | 616016321535 |
9 | 162802653228 |
10 | 53422433117 |
11 | 20724630779 |
12 | a42b093aa5 |
13 | 5064b1b591 |
14 | 282b09aa3b |
15 | 15ca07e112 |
hex | c7039a35d |
53422433117 has 2 divisors, whose sum is σ = 53422433118. Its totient is φ = 53422433116.
The previous prime is 53422433107. The next prime is 53422433153. The reversal of 53422433117 is 71133422435.
53422433117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 53000787961 + 421645156 = 230219^2 + 20534^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53422433117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53422433107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26711216558 + 26711216559.
It is an arithmetic number, because the mean of its divisors is an integer number (26711216559).
Almost surely, 253422433117 is an apocalyptic number.
It is an amenable number.
53422433117 is a deficient number, since it is larger than the sum of its proper divisors (1).
53422433117 is an equidigital number, since it uses as much as digits as its factorization.
53422433117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 60480, while the sum is 35.
The spelling of 53422433117 in words is "fifty-three billion, four hundred twenty-two million, four hundred thirty-three thousand, one hundred seventeen".
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