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53426137 is a prime number
BaseRepresentation
bin1100101111001…
…1011111011001
310201112022212211
43023303133121
5102134114022
65145035121
71216054222
oct313633731
9121468784
1053426137
1128180936
1215a85aa1
13b0b79cb
14714a249
154a54e77
hex32f37d9

53426137 has 2 divisors, whose sum is σ = 53426138. Its totient is φ = 53426136.

The previous prime is 53426129. The next prime is 53426141. The reversal of 53426137 is 73162435.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 46566976 + 6859161 = 6824^2 + 2619^2 .

It is a cyclic number.

It is not a de Polignac number, because 53426137 - 23 = 53426129 is a prime.

It is a super-5 number, since 5×534261375 (a number of 40 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 53426099 and 53426108.

It is not a weakly prime, because it can be changed into another prime (53426147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26713068 + 26713069.

It is an arithmetic number, because the mean of its divisors is an integer number (26713069).

Almost surely, 253426137 is an apocalyptic number.

It is an amenable number.

53426137 is a deficient number, since it is larger than the sum of its proper divisors (1).

53426137 is an equidigital number, since it uses as much as digits as its factorization.

53426137 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 15120, while the sum is 31.

The square root of 53426137 is about 7309.3185044845. The cubic root of 53426137 is about 376.6326140237.

The spelling of 53426137 in words is "fifty-three million, four hundred twenty-six thousand, one hundred thirty-seven".