Base | Representation |
---|---|
bin | 100110111000000101001… |
… | …1100000010011001001101 |
3 | 200220210111211110112201112 |
4 | 1031300022130002121031 |
5 | 1200020144244010341 |
6 | 15210332021421405 |
7 | 1061012233236230 |
oct | 115601234023115 |
9 | 20823454415645 |
10 | 5343114438221 |
11 | 178000289538a |
12 | 72364626a865 |
13 | 2c9b13287181 |
14 | 14687296b417 |
15 | 93ec0013aeb |
hex | 4dc0a70264d |
5343114438221 has 4 divisors (see below), whose sum is σ = 6106416500832. Its totient is φ = 4579812375612.
The previous prime is 5343114438199. The next prime is 5343114438229. The reversal of 5343114438221 is 1228344113435.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5343114438221 - 210 = 5343114437197 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5343114438229) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 381651031295 + ... + 381651031308.
It is an arithmetic number, because the mean of its divisors is an integer number (1526604125208).
Almost surely, 25343114438221 is an apocalyptic number.
It is an amenable number.
5343114438221 is a deficient number, since it is larger than the sum of its proper divisors (763302062611).
5343114438221 is an equidigital number, since it uses as much as digits as its factorization.
5343114438221 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 763302062610.
The product of its digits is 276480, while the sum is 41.
The spelling of 5343114438221 in words is "five trillion, three hundred forty-three billion, one hundred fourteen million, four hundred thirty-eight thousand, two hundred twenty-one".
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