Base | Representation |
---|---|
bin | 110001110000110111… |
… | …111100011100011001 |
3 | 12002220212012221221211 |
4 | 301300313330130121 |
5 | 1333412412234431 |
6 | 40314045303121 |
7 | 3601061510446 |
oct | 616067743431 |
9 | 162825187854 |
10 | 53433321241 |
11 | 2072a798123 |
12 | a432864aa1 |
13 | 5067161461 |
14 | 282c6d29cd |
15 | 15caed02b1 |
hex | c70dfc719 |
53433321241 has 8 divisors (see below), whose sum is σ = 53614342080. Its totient is φ = 53252379408.
The previous prime is 53433321239. The next prime is 53433321259. The reversal of 53433321241 is 14212333435.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53433321241 - 21 = 53433321239 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53433021241) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1542190 + ... + 1576456.
It is an arithmetic number, because the mean of its divisors is an integer number (6701792760).
Almost surely, 253433321241 is an apocalyptic number.
It is an amenable number.
53433321241 is a deficient number, since it is larger than the sum of its proper divisors (181020839).
53433321241 is a wasteful number, since it uses less digits than its factorization.
53433321241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39503.
The product of its digits is 25920, while the sum is 31.
Adding to 53433321241 its reverse (14212333435), we get a palindrome (67645654676).
The spelling of 53433321241 in words is "fifty-three billion, four hundred thirty-three million, three hundred twenty-one thousand, two hundred forty-one".
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