534334003 has 4 divisors (see below), whose sum is σ = 610667440. Its totient is φ = 458000568.

The previous prime is 534333991. The next prime is 534334013. The reversal of 534334003 is 300433435.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 534334003 - 2⁵ = 534333971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (534334013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38166708 + ... + 38166721.

It is an arithmetic number, because the mean of its divisors is an integer number (152666860).

Almost surely, 2^534334003 is an apocalyptic number.

534334003 is a deficient number, since it is larger than the sum of its proper divisors (76333437).

534334003 is an equidigital number, since it uses as much as digits as its factorization.

534334003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 76333436.

The product of its (nonzero) digits is 6480, while the sum is 25.

The square root of 534334003 is about 23115.6657485784. The cubic root of 534334003 is about 811.4671387879.

Adding to 534334003 its reverse (300433435), we get a palindrome (834767438).

The spelling of 534334003 in words is "five hundred thirty-four million, three hundred thirty-four thousand, three".