Base | Representation |
---|---|
bin | 111100101111110110111110… |
… | …0010001111101101001100111 |
3 | 2121001221201100121202020022001 |
4 | 1321133231330101331221213 |
5 | 1030014134444401041112 |
6 | 5132241523324550131 |
7 | 220360012100016142 |
oct | 17137557421755147 |
9 | 2531851317666261 |
10 | 534343261346407 |
11 | 145292782803637 |
12 | 4bb1b3790b2347 |
13 | 19c2047937a096 |
14 | 95d44cd64d059 |
15 | 41b9763ce2c57 |
hex | 1e5fb7c47da67 |
534343261346407 has 2 divisors, whose sum is σ = 534343261346408. Its totient is φ = 534343261346406.
The previous prime is 534343261346381. The next prime is 534343261346417. The reversal of 534343261346407 is 704643162343435.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 534343261346407 - 211 = 534343261344359 is a prime.
It is a super-2 number, since 2×5343432613464072 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (534343261346417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267171630673203 + 267171630673204.
It is an arithmetic number, because the mean of its divisors is an integer number (267171630673204).
Almost surely, 2534343261346407 is an apocalyptic number.
534343261346407 is a deficient number, since it is larger than the sum of its proper divisors (1).
534343261346407 is an equidigital number, since it uses as much as digits as its factorization.
534343261346407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52254720, while the sum is 55.
The spelling of 534343261346407 in words is "five hundred thirty-four trillion, three hundred forty-three billion, two hundred sixty-one million, three hundred forty-six thousand, four hundred seven".
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