Base | Representation |
---|---|
bin | 100110111000001110101… |
… | …1011110011011100111001 |
3 | 200220211100001011111000202 |
4 | 1031300131123303130321 |
5 | 1200021322341102441 |
6 | 15210423404411545 |
7 | 1061023153215032 |
oct | 115603533633471 |
9 | 20824301144022 |
10 | 5343433144121 |
11 | 1780156785896 |
12 | 723714b46bb5 |
13 | 2c9b64304347 |
14 | 1468a300da89 |
15 | 93edceba19b |
hex | 4dc1d6f3739 |
5343433144121 has 8 divisors (see below), whose sum is σ = 5657806201320. Its totient is φ = 5029066027008.
The previous prime is 5343433144109. The next prime is 5343433144123. The reversal of 5343433144121 is 1214413343435.
It can be written as a sum of positive squares in 4 ways, for example, as 1588131764521 + 3755301379600 = 1260211^2 + 1937860^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5343433144121 - 218 = 5343432881977 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5343433144123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 438185 + ... + 3298313.
It is an arithmetic number, because the mean of its divisors is an integer number (707225775165).
Almost surely, 25343433144121 is an apocalyptic number.
It is an amenable number.
5343433144121 is a deficient number, since it is larger than the sum of its proper divisors (314373057199).
5343433144121 is a wasteful number, since it uses less digits than its factorization.
5343433144121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2970043.
The product of its digits is 207360, while the sum is 38.
Adding to 5343433144121 its reverse (1214413343435), we get a palindrome (6557846487556).
The spelling of 5343433144121 in words is "five trillion, three hundred forty-three billion, four hundred thirty-three million, one hundred forty-four thousand, one hundred twenty-one".
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