Base | Representation |
---|---|
bin | 1111100011010010110… |
… | …01000100101100111011 |
3 | 1220002020100202001011011 |
4 | 13301221121010230323 |
5 | 32223314044001433 |
6 | 1045250241014351 |
7 | 53414355060355 |
oct | 7615131045473 |
9 | 1802210661134 |
10 | 534344125243 |
11 | 196683368085 |
12 | 876869243b7 |
13 | 3b508511786 |
14 | 1bc105a00d5 |
15 | dd75d0a3cd |
hex | 7c69644b3b |
534344125243 has 2 divisors, whose sum is σ = 534344125244. Its totient is φ = 534344125242.
The previous prime is 534344125213. The next prime is 534344125283. The reversal of 534344125243 is 342521443435.
It is an a-pointer prime, because the next prime (534344125283) can be obtained adding 534344125243 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 534344125243 - 213 = 534344117051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 534344125196 and 534344125205.
It is not a weakly prime, because it can be changed into another prime (534344125213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267172062621 + 267172062622.
It is an arithmetic number, because the mean of its divisors is an integer number (267172062622).
Almost surely, 2534344125243 is an apocalyptic number.
534344125243 is a deficient number, since it is larger than the sum of its proper divisors (1).
534344125243 is an equidigital number, since it uses as much as digits as its factorization.
534344125243 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 691200, while the sum is 40.
Adding to 534344125243 its reverse (342521443435), we get a palindrome (876865568678).
The spelling of 534344125243 in words is "five hundred thirty-four billion, three hundred forty-four million, one hundred twenty-five thousand, two hundred forty-three".
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