Base | Representation |
---|---|
bin | 111100101111111010010110… |
… | …1100101100010001101001011 |
3 | 2121001222102010020220110220202 |
4 | 1321133310231211202031023 |
5 | 1030014244341414331103 |
6 | 5132245124535042415 |
7 | 220360360202112551 |
oct | 17137645545421513 |
9 | 2531872106813822 |
10 | 534350531011403 |
11 | 1452958732a2537 |
12 | 4bb2086781040b |
13 | 19c210674bc4c2 |
14 | 95d49bcd23bd1 |
15 | 41b9a3c127988 |
hex | 1e5fd2d96234b |
534350531011403 has 2 divisors, whose sum is σ = 534350531011404. Its totient is φ = 534350531011402.
The previous prime is 534350531011391. The next prime is 534350531011411. The reversal of 534350531011403 is 304110135053435.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 534350531011403 - 238 = 534075653104459 is a prime.
It is not a weakly prime, because it can be changed into another prime (534350531011433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267175265505701 + 267175265505702.
It is an arithmetic number, because the mean of its divisors is an integer number (267175265505702).
Almost surely, 2534350531011403 is an apocalyptic number.
534350531011403 is a deficient number, since it is larger than the sum of its proper divisors (1).
534350531011403 is an equidigital number, since it uses as much as digits as its factorization.
534350531011403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162000, while the sum is 38.
Adding to 534350531011403 its reverse (304110135053435), we get a palindrome (838460666064838).
The spelling of 534350531011403 in words is "five hundred thirty-four trillion, three hundred fifty billion, five hundred thirty-one million, eleven thousand, four hundred three".
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