Base | Representation |
---|---|
bin | 111100101111111010010110… |
… | …1100101100010001101101001 |
3 | 2121001222102010020220110221212 |
4 | 1321133310231211202031221 |
5 | 1030014244341414331213 |
6 | 5132245124535042505 |
7 | 220360360202112623 |
oct | 17137645545421551 |
9 | 2531872106813855 |
10 | 534350531011433 |
11 | 1452958732a2564 |
12 | 4bb20867810435 |
13 | 19c210674bc516 |
14 | 95d49bcd23c13 |
15 | 41b9a3c1279a8 |
hex | 1e5fd2d962369 |
534350531011433 has 2 divisors, whose sum is σ = 534350531011434. Its totient is φ = 534350531011432.
The previous prime is 534350531011411. The next prime is 534350531011441. The reversal of 534350531011433 is 334110135053435.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 526793018688784 + 7557512322649 = 22951972^2 + 2749093^2 .
It is a cyclic number.
It is not a de Polignac number, because 534350531011433 - 238 = 534075653104489 is a prime.
It is not a weakly prime, because it can be changed into another prime (534350531011403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267175265505716 + 267175265505717.
It is an arithmetic number, because the mean of its divisors is an integer number (267175265505717).
Almost surely, 2534350531011433 is an apocalyptic number.
It is an amenable number.
534350531011433 is a deficient number, since it is larger than the sum of its proper divisors (1).
534350531011433 is an equidigital number, since it uses as much as digits as its factorization.
534350531011433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486000, while the sum is 41.
Adding to 534350531011433 its reverse (334110135053435), we get a palindrome (868460666064868).
The spelling of 534350531011433 in words is "five hundred thirty-four trillion, three hundred fifty billion, five hundred thirty-one million, eleven thousand, four hundred thirty-three".
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