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53435131 = 173143243
BaseRepresentation
bin1100101111010…
…1101011111011
310201112210012221
43023311223323
5102134411011
65145144511
71216122361
oct313655373
9121483187
1053435131
1128187672
1215a8b137
13b0bbb29
14714d631
154a57971
hex32f5afb

53435131 has 4 divisors (see below), whose sum is σ = 56578392. Its totient is φ = 50291872.

The previous prime is 53435093. The next prime is 53435147. The reversal of 53435131 is 13153435.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53435131 - 223 = 45046523 is a prime.

It is a super-2 number, since 2×534351312 = 5710626449974322, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53435096 and 53435105.

It is not an unprimeable number, because it can be changed into a prime (53435531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1571605 + ... + 1571638.

It is an arithmetic number, because the mean of its divisors is an integer number (14144598).

Almost surely, 253435131 is an apocalyptic number.

53435131 is a deficient number, since it is larger than the sum of its proper divisors (3143261).

53435131 is a wasteful number, since it uses less digits than its factorization.

53435131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3143260.

The product of its digits is 2700, while the sum is 25.

The square root of 53435131 is about 7309.9337206298. The cubic root of 53435131 is about 376.6537475229.

Adding to 53435131 its reverse (13153435), we get a palindrome (66588566).

The spelling of 53435131 in words is "fifty-three million, four hundred thirty-five thousand, one hundred thirty-one".

Divisors: 1 17 3143243 53435131