Base | Representation |
---|---|
bin | 11000010011001010101101… |
… | …00100010111001000000111 |
3 | 21000012100102211001101001201 |
4 | 30021211112210113020013 |
5 | 24000440131432031043 |
6 | 305351433100003331 |
7 | 14153363411053360 |
oct | 1411452644271007 |
9 | 230170384041051 |
10 | 53435140502023 |
11 | 16031796842475 |
12 | 5bb0108530547 |
13 | 23a7bb1c39877 |
14 | d2a3bb704b67 |
15 | 629e85d32c4d |
hex | 309956917207 |
53435140502023 has 4 divisors (see below), whose sum is σ = 61068732002320. Its totient is φ = 45801549001728.
The previous prime is 53435140501993. The next prime is 53435140502047. The reversal of 53435140502023 is 32020504153435.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53435140502023 - 213 = 53435140493831 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53435140502923) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3816795750138 + ... + 3816795750151.
It is an arithmetic number, because the mean of its divisors is an integer number (15267183000580).
Almost surely, 253435140502023 is an apocalyptic number.
53435140502023 is a deficient number, since it is larger than the sum of its proper divisors (7633591500297).
53435140502023 is an equidigital number, since it uses as much as digits as its factorization.
53435140502023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7633591500296.
The product of its (nonzero) digits is 216000, while the sum is 37.
Adding to 53435140502023 its reverse (32020504153435), we get a palindrome (85455644655458).
The spelling of 53435140502023 in words is "fifty-three trillion, four hundred thirty-five billion, one hundred forty million, five hundred two thousand, twenty-three".
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