Base | Representation |
---|---|
bin | 111100110000010111100101… |
… | …1100100010101100111110111 |
3 | 2121002012102011111121100221202 |
4 | 1321200233023210111213313 |
5 | 1030021311430111234431 |
6 | 5132334030313003115 |
7 | 220365042016416065 |
oct | 17140571344254767 |
9 | 2532172144540852 |
10 | 534413311039991 |
11 | 14530a459a57189 |
12 | 4bb30a686b349b |
13 | 19c26c60ba3506 |
14 | 95d7a56abd035 |
15 | 41bb4b396c8cb |
hex | 1e60bcb9159f7 |
534413311039991 has 2 divisors, whose sum is σ = 534413311039992. Its totient is φ = 534413311039990.
The previous prime is 534413311039967. The next prime is 534413311040009. The reversal of 534413311039991 is 199930113314435.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 534413311039991 - 210 = 534413311038967 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (534413311039901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267206655519995 + 267206655519996.
It is an arithmetic number, because the mean of its divisors is an integer number (267206655519996).
Almost surely, 2534413311039991 is an apocalyptic number.
534413311039991 is a deficient number, since it is larger than the sum of its proper divisors (1).
534413311039991 is an equidigital number, since it uses as much as digits as its factorization.
534413311039991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4723920, while the sum is 56.
The spelling of 534413311039991 in words is "five hundred thirty-four trillion, four hundred thirteen billion, three hundred eleven million, thirty-nine thousand, nine hundred ninety-one".
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