Base | Representation |
---|---|
bin | 110001110001011111… |
… | …010010010100001001 |
3 | 12002221120121221000012 |
4 | 301301133102110021 |
5 | 1333423032300231 |
6 | 40315054321305 |
7 | 3601245253211 |
oct | 616137222411 |
9 | 162846557005 |
10 | 53443634441 |
11 | 207355a162a |
12 | a4361b9235 |
13 | 5069332742 |
14 | 282dc19241 |
15 | 15cbd6ae2b |
hex | c717d2509 |
53443634441 has 2 divisors, whose sum is σ = 53443634442. Its totient is φ = 53443634440.
The previous prime is 53443634429. The next prime is 53443634477. The reversal of 53443634441 is 14443634435.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 28089760000 + 25353874441 = 167600^2 + 159229^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53443634441 is a prime.
It is a super-3 number, since 3×534436344413 (a number of 33 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (53443034441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26721817220 + 26721817221.
It is an arithmetic number, because the mean of its divisors is an integer number (26721817221).
Almost surely, 253443634441 is an apocalyptic number.
It is an amenable number.
53443634441 is a deficient number, since it is larger than the sum of its proper divisors (1).
53443634441 is an equidigital number, since it uses as much as digits as its factorization.
53443634441 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 829440, while the sum is 41.
The spelling of 53443634441 in words is "fifty-three billion, four hundred forty-three million, six hundred thirty-four thousand, four hundred forty-one".
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