Base | Representation |
---|---|
bin | 1111100011100110101… |
… | …11010000001100110101 |
3 | 1220002200000112111201011 |
4 | 13301303113100030311 |
5 | 32224134410421323 |
6 | 1045315014432221 |
7 | 53421456051661 |
oct | 7616327201465 |
9 | 1802600474634 |
10 | 534511420213 |
11 | 196759842291 |
12 | 87712962671 |
13 | 3b534087794 |
14 | 1bc288ab8a1 |
15 | dd8585420d |
hex | 7c735d0335 |
534511420213 has 4 divisors (see below), whose sum is σ = 534513031200. Its totient is φ = 534509809228.
The previous prime is 534511420139. The next prime is 534511420217. The reversal of 534511420213 is 312024115435.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 534511420213 - 229 = 533974549301 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (534511420217) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 104395 + ... + 1039192.
It is an arithmetic number, because the mean of its divisors is an integer number (133628257800).
Almost surely, 2534511420213 is an apocalyptic number.
It is an amenable number.
534511420213 is a deficient number, since it is larger than the sum of its proper divisors (1610987).
534511420213 is a wasteful number, since it uses less digits than its factorization.
534511420213 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1610986.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 534511420213 its reverse (312024115435), we get a palindrome (846535535648).
The spelling of 534511420213 in words is "five hundred thirty-four billion, five hundred eleven million, four hundred twenty thousand, two hundred thirteen".
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