Base | Representation |
---|---|
bin | 11000010011101000110110… |
… | …00101110111000111000001 |
3 | 21000020220012120101001120220 |
4 | 30021310123011313013001 |
5 | 24001221302031120001 |
6 | 305403110520453253 |
7 | 14154505412665350 |
oct | 1411643305670701 |
9 | 230226176331526 |
10 | 53451322520001 |
11 | 160386400a904a |
12 | 5bb328391a229 |
13 | 23a9590622333 |
14 | d2b0b48d7997 |
15 | 62a5d17cec36 |
hex | 309d1b1771c1 |
53451322520001 has 16 divisors (see below), whose sum is σ = 86240789276544. Its totient is φ = 28746929758464.
The previous prime is 53451322519943. The next prime is 53451322520003. The reversal of 53451322520001 is 10002522315435.
It is not a de Polignac number, because 53451322520001 - 27 = 53451322519873 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53451322520003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 74861795890 + ... + 74861796603.
It is an arithmetic number, because the mean of its divisors is an integer number (5390049329784).
Almost surely, 253451322520001 is an apocalyptic number.
53451322520001 is a gapful number since it is divisible by the number (51) formed by its first and last digit.
It is an amenable number.
53451322520001 is a deficient number, since it is larger than the sum of its proper divisors (32789466756543).
53451322520001 is a wasteful number, since it uses less digits than its factorization.
53451322520001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 149723592520.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 53451322520001 its reverse (10002522315435), we get a palindrome (63453844835436).
The spelling of 53451322520001 in words is "fifty-three trillion, four hundred fifty-one billion, three hundred twenty-two million, five hundred twenty thousand, one".
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