Base | Representation |
---|---|
bin | 11000010011101000110110… |
… | …00101110111000110000111 |
3 | 21000020220012120101001111202 |
4 | 30021310123011313012013 |
5 | 24001221302031114233 |
6 | 305403110520453115 |
7 | 14154505412665235 |
oct | 1411643305670607 |
9 | 230226176331452 |
10 | 53451322519943 |
11 | 160386400a8aa7 |
12 | 5bb328391a19b |
13 | 23a95906222ba |
14 | d2b0b48d7955 |
15 | 62a5d17cebe8 |
hex | 309d1b177187 |
53451322519943 has 2 divisors, whose sum is σ = 53451322519944. Its totient is φ = 53451322519942.
The previous prime is 53451322519877. The next prime is 53451322520003. The reversal of 53451322519943 is 34991522315435.
53451322519943 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53451322519943 - 230 = 53450248778119 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53451322549943) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26725661259971 + 26725661259972.
It is an arithmetic number, because the mean of its divisors is an integer number (26725661259972).
Almost surely, 253451322519943 is an apocalyptic number.
53451322519943 is a deficient number, since it is larger than the sum of its proper divisors (1).
53451322519943 is an equidigital number, since it uses as much as digits as its factorization.
53451322519943 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 17496000, while the sum is 56.
The spelling of 53451322519943 in words is "fifty-three trillion, four hundred fifty-one billion, three hundred twenty-two million, five hundred nineteen thousand, nine hundred forty-three".
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